Integrand size = 16, antiderivative size = 112 \[ \int x^3 (a+b x)^5 (A+B x) \, dx=-\frac {a^3 (A b-a B) (a+b x)^6}{6 b^5}+\frac {a^2 (3 A b-4 a B) (a+b x)^7}{7 b^5}-\frac {3 a (A b-2 a B) (a+b x)^8}{8 b^5}+\frac {(A b-4 a B) (a+b x)^9}{9 b^5}+\frac {B (a+b x)^{10}}{10 b^5} \]
-1/6*a^3*(A*b-B*a)*(b*x+a)^6/b^5+1/7*a^2*(3*A*b-4*B*a)*(b*x+a)^7/b^5-3/8*a *(A*b-2*B*a)*(b*x+a)^8/b^5+1/9*(A*b-4*B*a)*(b*x+a)^9/b^5+1/10*B*(b*x+a)^10 /b^5
Time = 0.01 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.04 \[ \int x^3 (a+b x)^5 (A+B x) \, dx=\frac {1}{4} a^5 A x^4+\frac {1}{5} a^4 (5 A b+a B) x^5+\frac {5}{6} a^3 b (2 A b+a B) x^6+\frac {10}{7} a^2 b^2 (A b+a B) x^7+\frac {5}{8} a b^3 (A b+2 a B) x^8+\frac {1}{9} b^4 (A b+5 a B) x^9+\frac {1}{10} b^5 B x^{10} \]
(a^5*A*x^4)/4 + (a^4*(5*A*b + a*B)*x^5)/5 + (5*a^3*b*(2*A*b + a*B)*x^6)/6 + (10*a^2*b^2*(A*b + a*B)*x^7)/7 + (5*a*b^3*(A*b + 2*a*B)*x^8)/8 + (b^4*(A *b + 5*a*B)*x^9)/9 + (b^5*B*x^10)/10
Time = 0.25 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {85, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^3 (a+b x)^5 (A+B x) \, dx\) |
\(\Big \downarrow \) 85 |
\(\displaystyle \int \left (\frac {a^3 (a+b x)^5 (a B-A b)}{b^4}-\frac {a^2 (a+b x)^6 (4 a B-3 A b)}{b^4}+\frac {(a+b x)^8 (A b-4 a B)}{b^4}+\frac {3 a (a+b x)^7 (2 a B-A b)}{b^4}+\frac {B (a+b x)^9}{b^4}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {a^3 (a+b x)^6 (A b-a B)}{6 b^5}+\frac {a^2 (a+b x)^7 (3 A b-4 a B)}{7 b^5}+\frac {(a+b x)^9 (A b-4 a B)}{9 b^5}-\frac {3 a (a+b x)^8 (A b-2 a B)}{8 b^5}+\frac {B (a+b x)^{10}}{10 b^5}\) |
-1/6*(a^3*(A*b - a*B)*(a + b*x)^6)/b^5 + (a^2*(3*A*b - 4*a*B)*(a + b*x)^7) /(7*b^5) - (3*a*(A*b - 2*a*B)*(a + b*x)^8)/(8*b^5) + ((A*b - 4*a*B)*(a + b *x)^9)/(9*b^5) + (B*(a + b*x)^10)/(10*b^5)
3.2.21.3.1 Defintions of rubi rules used
Int[((d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_))*((e_) + (f_.)*(x_))^(p_.), x_] : > Int[ExpandIntegrand[(a + b*x)*(d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, d, e, f, n}, x] && IGtQ[p, 0] && (NeQ[n, -1] || EqQ[p, 1]) && NeQ[b*e + a* f, 0] && ( !IntegerQ[n] || LtQ[9*p + 5*n, 0] || GeQ[n + p + 1, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, d, e, f])) && (NeQ[n + p + 3, 0] || EqQ[p, 1])
Time = 0.39 (sec) , antiderivative size = 120, normalized size of antiderivative = 1.07
method | result | size |
norman | \(\frac {b^{5} B \,x^{10}}{10}+\left (\frac {1}{9} b^{5} A +\frac {5}{9} a \,b^{4} B \right ) x^{9}+\left (\frac {5}{8} a \,b^{4} A +\frac {5}{4} a^{2} b^{3} B \right ) x^{8}+\left (\frac {10}{7} a^{2} b^{3} A +\frac {10}{7} a^{3} b^{2} B \right ) x^{7}+\left (\frac {5}{3} a^{3} b^{2} A +\frac {5}{6} a^{4} b B \right ) x^{6}+\left (a^{4} b A +\frac {1}{5} a^{5} B \right ) x^{5}+\frac {a^{5} A \,x^{4}}{4}\) | \(120\) |
default | \(\frac {b^{5} B \,x^{10}}{10}+\frac {\left (b^{5} A +5 a \,b^{4} B \right ) x^{9}}{9}+\frac {\left (5 a \,b^{4} A +10 a^{2} b^{3} B \right ) x^{8}}{8}+\frac {\left (10 a^{2} b^{3} A +10 a^{3} b^{2} B \right ) x^{7}}{7}+\frac {\left (10 a^{3} b^{2} A +5 a^{4} b B \right ) x^{6}}{6}+\frac {\left (5 a^{4} b A +a^{5} B \right ) x^{5}}{5}+\frac {a^{5} A \,x^{4}}{4}\) | \(124\) |
gosper | \(\frac {1}{10} b^{5} B \,x^{10}+\frac {1}{9} x^{9} b^{5} A +\frac {5}{9} x^{9} a \,b^{4} B +\frac {5}{8} x^{8} a \,b^{4} A +\frac {5}{4} x^{8} a^{2} b^{3} B +\frac {10}{7} x^{7} a^{2} b^{3} A +\frac {10}{7} x^{7} a^{3} b^{2} B +\frac {5}{3} x^{6} a^{3} b^{2} A +\frac {5}{6} x^{6} a^{4} b B +x^{5} a^{4} b A +\frac {1}{5} x^{5} a^{5} B +\frac {1}{4} a^{5} A \,x^{4}\) | \(125\) |
risch | \(\frac {1}{10} b^{5} B \,x^{10}+\frac {1}{9} x^{9} b^{5} A +\frac {5}{9} x^{9} a \,b^{4} B +\frac {5}{8} x^{8} a \,b^{4} A +\frac {5}{4} x^{8} a^{2} b^{3} B +\frac {10}{7} x^{7} a^{2} b^{3} A +\frac {10}{7} x^{7} a^{3} b^{2} B +\frac {5}{3} x^{6} a^{3} b^{2} A +\frac {5}{6} x^{6} a^{4} b B +x^{5} a^{4} b A +\frac {1}{5} x^{5} a^{5} B +\frac {1}{4} a^{5} A \,x^{4}\) | \(125\) |
parallelrisch | \(\frac {1}{10} b^{5} B \,x^{10}+\frac {1}{9} x^{9} b^{5} A +\frac {5}{9} x^{9} a \,b^{4} B +\frac {5}{8} x^{8} a \,b^{4} A +\frac {5}{4} x^{8} a^{2} b^{3} B +\frac {10}{7} x^{7} a^{2} b^{3} A +\frac {10}{7} x^{7} a^{3} b^{2} B +\frac {5}{3} x^{6} a^{3} b^{2} A +\frac {5}{6} x^{6} a^{4} b B +x^{5} a^{4} b A +\frac {1}{5} x^{5} a^{5} B +\frac {1}{4} a^{5} A \,x^{4}\) | \(125\) |
1/10*b^5*B*x^10+(1/9*b^5*A+5/9*a*b^4*B)*x^9+(5/8*a*b^4*A+5/4*a^2*b^3*B)*x^ 8+(10/7*a^2*b^3*A+10/7*a^3*b^2*B)*x^7+(5/3*a^3*b^2*A+5/6*a^4*b*B)*x^6+(a^4 *b*A+1/5*a^5*B)*x^5+1/4*a^5*A*x^4
Time = 0.22 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.06 \[ \int x^3 (a+b x)^5 (A+B x) \, dx=\frac {1}{10} \, B b^{5} x^{10} + \frac {1}{4} \, A a^{5} x^{4} + \frac {1}{9} \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{9} + \frac {5}{8} \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{8} + \frac {10}{7} \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x^{7} + \frac {5}{6} \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{6} + \frac {1}{5} \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x^{5} \]
1/10*B*b^5*x^10 + 1/4*A*a^5*x^4 + 1/9*(5*B*a*b^4 + A*b^5)*x^9 + 5/8*(2*B*a ^2*b^3 + A*a*b^4)*x^8 + 10/7*(B*a^3*b^2 + A*a^2*b^3)*x^7 + 5/6*(B*a^4*b + 2*A*a^3*b^2)*x^6 + 1/5*(B*a^5 + 5*A*a^4*b)*x^5
Time = 0.03 (sec) , antiderivative size = 134, normalized size of antiderivative = 1.20 \[ \int x^3 (a+b x)^5 (A+B x) \, dx=\frac {A a^{5} x^{4}}{4} + \frac {B b^{5} x^{10}}{10} + x^{9} \left (\frac {A b^{5}}{9} + \frac {5 B a b^{4}}{9}\right ) + x^{8} \cdot \left (\frac {5 A a b^{4}}{8} + \frac {5 B a^{2} b^{3}}{4}\right ) + x^{7} \cdot \left (\frac {10 A a^{2} b^{3}}{7} + \frac {10 B a^{3} b^{2}}{7}\right ) + x^{6} \cdot \left (\frac {5 A a^{3} b^{2}}{3} + \frac {5 B a^{4} b}{6}\right ) + x^{5} \left (A a^{4} b + \frac {B a^{5}}{5}\right ) \]
A*a**5*x**4/4 + B*b**5*x**10/10 + x**9*(A*b**5/9 + 5*B*a*b**4/9) + x**8*(5 *A*a*b**4/8 + 5*B*a**2*b**3/4) + x**7*(10*A*a**2*b**3/7 + 10*B*a**3*b**2/7 ) + x**6*(5*A*a**3*b**2/3 + 5*B*a**4*b/6) + x**5*(A*a**4*b + B*a**5/5)
Time = 0.19 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.06 \[ \int x^3 (a+b x)^5 (A+B x) \, dx=\frac {1}{10} \, B b^{5} x^{10} + \frac {1}{4} \, A a^{5} x^{4} + \frac {1}{9} \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{9} + \frac {5}{8} \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{8} + \frac {10}{7} \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x^{7} + \frac {5}{6} \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{6} + \frac {1}{5} \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x^{5} \]
1/10*B*b^5*x^10 + 1/4*A*a^5*x^4 + 1/9*(5*B*a*b^4 + A*b^5)*x^9 + 5/8*(2*B*a ^2*b^3 + A*a*b^4)*x^8 + 10/7*(B*a^3*b^2 + A*a^2*b^3)*x^7 + 5/6*(B*a^4*b + 2*A*a^3*b^2)*x^6 + 1/5*(B*a^5 + 5*A*a^4*b)*x^5
Time = 0.27 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.11 \[ \int x^3 (a+b x)^5 (A+B x) \, dx=\frac {1}{10} \, B b^{5} x^{10} + \frac {5}{9} \, B a b^{4} x^{9} + \frac {1}{9} \, A b^{5} x^{9} + \frac {5}{4} \, B a^{2} b^{3} x^{8} + \frac {5}{8} \, A a b^{4} x^{8} + \frac {10}{7} \, B a^{3} b^{2} x^{7} + \frac {10}{7} \, A a^{2} b^{3} x^{7} + \frac {5}{6} \, B a^{4} b x^{6} + \frac {5}{3} \, A a^{3} b^{2} x^{6} + \frac {1}{5} \, B a^{5} x^{5} + A a^{4} b x^{5} + \frac {1}{4} \, A a^{5} x^{4} \]
1/10*B*b^5*x^10 + 5/9*B*a*b^4*x^9 + 1/9*A*b^5*x^9 + 5/4*B*a^2*b^3*x^8 + 5/ 8*A*a*b^4*x^8 + 10/7*B*a^3*b^2*x^7 + 10/7*A*a^2*b^3*x^7 + 5/6*B*a^4*b*x^6 + 5/3*A*a^3*b^2*x^6 + 1/5*B*a^5*x^5 + A*a^4*b*x^5 + 1/4*A*a^5*x^4
Time = 0.04 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.95 \[ \int x^3 (a+b x)^5 (A+B x) \, dx=x^5\,\left (\frac {B\,a^5}{5}+A\,b\,a^4\right )+x^9\,\left (\frac {A\,b^5}{9}+\frac {5\,B\,a\,b^4}{9}\right )+\frac {A\,a^5\,x^4}{4}+\frac {B\,b^5\,x^{10}}{10}+\frac {10\,a^2\,b^2\,x^7\,\left (A\,b+B\,a\right )}{7}+\frac {5\,a^3\,b\,x^6\,\left (2\,A\,b+B\,a\right )}{6}+\frac {5\,a\,b^3\,x^8\,\left (A\,b+2\,B\,a\right )}{8} \]